44=2t+5t^2

Solution for 44=2t+5t^2 equation:

44=2t+5t^2

We move all terms to the left:

44-(2t+5t^2)=0

We get rid of parentheses

-5t^2-2t+44=0

a = -5; b = -2; c = +44;
Δ = b2-4ac
Δ = -22-4·(-5)·44
Δ = 884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{884}=\sqrt{4*221}=\sqrt{4}*\sqrt{221}=2\sqrt{221}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{221}}{2*-5}=\frac{2-2\sqrt{221}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{221}}{2*-5}=\frac{2+2\sqrt{221}}{-10}
$